1.

A mass m = 8kg is attached to a spring as shown in figure and held in position so that the spring remains unstretched. The spring constant is 200 N//m. The mass m is then released and begins to undergo small oscillations. Find the maximum velocity of the mass (g =10 m//s^(2))

Answer»

SOLUTION :Mean position will be at K , x= mg or `x= (mg)/(k)= (8 xx 10)/(200)= (2)/(5) = 0.4m`
This is also the AMPLITUDE of oscillation i.e., A= 0.4m
Now `v_("max")= Aomega= Asqrt((k)/(m))= (0.4)sqrt((200)/(8))= 2m//s`


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