A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is

A mass is whirled in a circular path with constant angular velocity an

1.	A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is
Answer» `(L)/(4)` `(L)/(2)` L 2 L Solution :L = `mr^(2) omega` . For GIVEN m and `omega , L prop R^(2)`. If r is halved , the ANGULAR momentum L becomes one -FOURTH .