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A mass attached to one end of a string crosses top - most point on a vertical circle with critical speed. Its centripetal acceleration when string becomes horizontal will be (where, g=gravitational acceleration)A. glancing angleB. 3gC. 4gD. 6g |
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Answer» Correct Answer - B We know that, velocity of particle at top - most point on vertical circle, `(v_(top))=sqrt(3rg)` . . . (i) But centripetal acceleration `(a_(c))=(v^(2))/(r)` `:." "a_(c)(sqrt(3rg)^(2))/(r)" "` [from Eq. (i)] `a_(c)=(3rg)/(r)` `a_(c)=3g` |
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