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A marble 100g dropped from top of a tower of height 5m and comes to rest when it hit the ground. the change in momentum in kg m/s of the marbel when it hit the groud is no spam pls |
| Answer» E taken by the body to FALL from the HEIGHT h ist= g2h ....................................(1)After the first rebound, time taken to rise to height h 1 and coming back ist 1 =2 g2h 1 t 1 =2 g2e 2 h t 1 =2e g2h Time taken in rising to height h 1 and coming back ist 2 =2e 2 g2h Time taken by the body in coming to restt 3 = g2h +2e g2h +2e 2 g2h t 3 = g2h +2e g2h [1+e+e 2 +−−−−−−−−−−.]t 3 = g2h +2e g2h [ 1−e1 ]t 3 = g2h [1+ 1−e2e ]t 3 = g2h [ 1−e1−e+2e ]t 3 = g2h [ 1−e1+e ]t 3 =t[ 1−e1+e ]........................from (1)PLZ MARK AS BRAINLIESTCOULDN'T TYPE IT PERFECTLY SORRY | |