A man whose mass is 80 kg stands on his feet on a floor. The total area of contact of his two feet with the floor is 0.032 m 2 (Take, g= 10ms -2 ) How much is the pressure exerted by him on the floor?

A man whose mass is 80 kg stands on his feet on a floor. The total are

1.	A man whose mass is 80 kg stands on his feet on a floor. The total area of contact of his two feet with the floor is 0.032 m 2 (Take, g= 10ms -2 ) How much is the pressure exerted by him on the floor?
Answer» 24,456.52N/m2.F=mg=90x10=900Nans)P=F/A = 900N/0.03m2=24,456.52N/m2Hope it HELPS :)EXPLANATION:

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A man whose mass is 80 kg stands on his feet on a floor. The total area of contact of his two feet with the floor is 0.032 m 2 (Take, g= 10ms -2 ) How much is the pressure exerted by him on the floor?

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