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a man wheing 60 kg is running along a rail with a velocity of 18km/hr and jumps into a car of 1 quintal what is the velocity |
Answer» Mass of man (m1) = 60kg
Initial velocity of man (U1) = 18 km/h=18x5/18=5m/sFinal velocity of man (v1) = (v2) = vMass of car (m2)= 100kgInitial velocity of car (u2) = 0 (as it is in rest)Final velocity of car (v2) = vAccording to LAW of conservation of momentum,m1u1 +m2u2 = M1V1 + m2v260x5 + 100x0 = 60 x v + 100 x v300+0 = 160vv = 300/160v = 1.875 m/s |
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