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A man was driving a 1800kg car at the speed of 35m/s .when he reached near school,he slowed down his car to 15m/s.what was the change in the kinetic energy of the car? |
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Answer» Explanation: change in KE = KEF - KEi = I/2*1800*(15²-35²) J = 900*(225-1225) J = 900*-1000 J = -900000 JOULES |
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