1.

A man was driving a 1800kg car at the speed of 35m/s .when he reached near school,he slowed down his car to 15m/s.what was the change in the kinetic energy of the car?

Answer»

Explanation:

change in KE = KEF - KEi

= I/2*1800*(15²-35²) J

= 900*(225-1225) J

= 900*-1000 J

= -900000 JOULES



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