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| 1. |
A man walks on a straight road from his home to a market 2.5 km away with a speed of 5 km/h. Finding the market closed, he instantly turnsand walks back home with a speed of 7.5 km/h. What is the (a) magnitudeof average velocity and (b) average speed of the man over the time intervalO to 50 min.1) O, 4 kmph 2)0,6 kmph 3) 0,8 kmph 4) 0,12 kmph |
| Answer» OPT 2Explanation:velocity=displacement/timedisplacement=0 HENCE velocity=0speed=total distance/total timev=(5)/5/6 =6 kmphhope it helped and pls MARK as BRAINLIEST:) | |