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A man walks at the speed of 4km/h.A train coming from behind him at 22km/h passes by him in 30seconds.Find the length of the train |
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Answer» speed of the MAN, u = 4 km/hr = 10/9 m/s speed of the train, v = 55/9 m/s length of the train, b = X metre length of the man, a = 0 metres time TAKEN by the train to CROSS the man = (a+b)/(u-v) seconds therefore, (0+x)/[(10/9)+(55/9)] = 30 x/(45/9)= 30 x/5 = 30 x = 150 therefore the length of the train = 150 metres |
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