A man throws ball with the same speed vertically upwards one after the

1.	A man throws ball with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time ? (Given g = 9.8m/s2 )
Answer» A man THROWS ball with the same speed VERTICALLY upwards one after the other at an interval of 2 SECONDS. What should be the speed of the throw so that more than two balls are in the sky at any time ? (GIVEN g=9.8m/s 2 ) ANSWER The correct option is A. We have t=2s When the ball is thrown upward the final velocity BECOME zero. Therefore, v=u+at 0=u−gt Here, g is acceleration due to gravity u=gt =9.8×2=19.6 m/s Thus, when he throws a ball with a minimum speed of 19.6m/s in a time interval of 2s. Then two balls can be in the air simultaneously.

A man throws ball with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time ? (Given g = 9.8m/s2 )

Answer»

A man THROWS ball with the same speed VERTICALLY upwards one after the other at an interval of 2 SECONDS. What should be the speed of the throw so that more than two balls are in the sky at any time ? (GIVEN g=9.8m/s

)

ANSWER

The correct option is A.

We have t=2s

When the ball is thrown upward the final velocity BECOME zero.

Therefore,

v=u+at

0=u−gt

Here, g is acceleration due to gravity

u=gt

=9.8×2=19.6 m/s

Thus, when he throws a ball with a minimum speed of 19.6m/s in a time interval of 2s.

Then two balls can be in the air simultaneously.

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