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A man swims from a point A on the bank of a river if width 100 m. When he swims perpendicular to the water current, he reaches the other bank 50 m downstream. The angle to the bank at which he should swim, to reach the directly opposite point B on the other bank is. . |
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Answer» `10^@` upstream `tan THETA = (v_w)/(v_m) = (50)/(100) = (1)/(2) or v_m = 2v_w` Refer to (Fig .S5.68) (B), `sin prop = (v_w)/(v_m) = (v_w)/(2 v_w) = (1)/(2)` or `theta = 30^@` So, it is `60^@` upstream. (a) ,
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