1.

A man standing between 2 parallel eliffs fires a gun. He hearns two echos one after 3 seconds and other after 5 seconds. The separation between the two cliffs is 1360 m, what is the speed of sound?

Answer»

distance (s) = 1360 m, 

time for first echo = 3 s, 

time for second echo = 5 s 

To Find : speed of sound (v)

Formula : speed = distance/time

Calculation :

Time for first echo = 3 s 

∴ time taken by sound to travel given distance t1 

= 3/2  = 1.5 s

Time for second echo = 5 s 

∴ time taken by sound to travel given distance t2 

= 5/2 = 2.5 s

∴Total time taken by sound to travel given distance, 

T = 1.5 + 2.5 = 4 s

From formula,

v = 1360/4

∴v = 340 m/s



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