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A man standing between 2 parallel eliffs fires a gun. He hearns two echos one after 3 seconds and other after 5 seconds. The separation between the two cliffs is 1360 m, what is the speed of sound? |
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Answer» distance (s) = 1360 m, time for first echo = 3 s, time for second echo = 5 s To Find : speed of sound (v) Formula : speed = distance/time Calculation : Time for first echo = 3 s ∴ time taken by sound to travel given distance t1 = 3/2 = 1.5 s Time for second echo = 5 s ∴ time taken by sound to travel given distance t2 = 5/2 = 2.5 s ∴Total time taken by sound to travel given distance, T = 1.5 + 2.5 = 4 s From formula, v = 1360/4 ∴v = 340 m/s |
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