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a man offers 2 flowers on even days,3 flowers on odd days divisible by 3 and offer 2 extra flowers on the days divisible by 5,how many flowers did he offer in april 1984 |
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Answer» Answer: Step-by-step explanation: No. of days in April 1984 = 30 No. of days he will OFFER 2 flowers = 15 days( 15 days r even ) Flowers given = 30 (15*2) No. of days he will offer 3 flowers = 5 days( 5 days r odd N DIVISIBLE by 3 ) Flowers given = 25 (5*5) No. of times he'll give 2 extra = 6 ( 6days divisible by 5 ) Flowers given = 12 (6*2) So, Total flowers offered= 30 + 25 + 12 = 67 flowers offered in the month of April 1984 |
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