1.

a man of weight W is standing on a lift which is moving upwards with an acceleration a. what is the apparent weight of the man

Answer»

Upward Acceleration=a
DOWNWARD Acceleration=g
Since lift is moving up so upward acceleration is GREATER than downward acceleration hence, we have NET acceleration=(a-g) ACTING upward, So
weight, W=mass of the man× (a-g) acceleration



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