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A man of 60 kg moves in a lift of constant velocity 5 m/s. What is the reactive force acting on the man by the elevator? |
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Answer» Here, Waight of the MAN is 60KG, and velocity is 5m/s^-2..so. the reactive or UPWARD force on the man by the LIFT or by the elevator is N=m(g+a)=60(9.8+5)=60*49=2940... |
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