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a man of 55 kg is holding a bucket of mass 25 kg. he walks 50 m on a level road at a constant speed of 3ms -1 and then climbs up a hill of hight 20m. the work done by the man is ( g = 10 ms -2 ) |
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Answer» orce = mass × gravitation accelerationf = 55 + 25 × 10f = 80 × 10 f = 800 Nnow ,total distance covered by the man = 50 + 20 = 70 mwork done = FORCE × displacement w = 800 × 70 w = 56000 J therefore work done by the man is 56000 J |
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