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A man `M_(1)` of mass `80 kg` runs up a statircase in `15 s`. Another man `M_(2)` also of mass `80 kg` runs up the same staricase in `20 s`. The ratio of the power devlopment by then will be:A. 1B. `(4)/(3)`C. `(16)/(9)`D. none of these |
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Answer» Correct Answer - B Power `P=` Work time Work done by the will be same . Hence `(P_(1))/(P_(2)) = (t_(2))/(t_(1)) = (20)/(15) = (4)/(3)` . |
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