A man is standing between source and cliff. When he start moving along line joining him and source, he hears 10 beats per second. Velocity of man is : (Frequency of source = 60 Hz, Velocity of sound = 330 m/s)

A man is standing between source and cliff. When he start moving along

1.	A man is standing between source and cliff. When he start moving along line joining him and source, he hears 10 beats per second. Velocity of man is : (Frequency of source = 60 Hz, Velocity of sound = 330 m/s)
Answer» y of man = 27.5 m/s EXPLANATION :Given :The hears 10 beats per seconds.Velocity of man is : (FREQUENCY of source = 60 Hz, Velocity of sound = 330 m/s.To Find :The Velocity of man .Solution :We know about Doppler's Effect equation.In which,For determining the frequency : ƒ = observed frequency,c = speed of sound. Vs = velocity of source [ It will be negative if it's moving toward the observer. ] ƒ₀ = emitted frequency of source.So,Consider the :The person is moving TOWARDS - The bluff.The frequency that can be heard directly from the source as - f₂he frequency heard by observer after omitting from the bluff as - f₃ After finding f₂ & f₃ , These two frequencies shall produce beats of 10 Hz.So,f₂ :f₃ :Now :Beats of 10 Hz :Hence,The velocity of man will be 27.5 m/s .

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A man is standing between source and cliff. When he start moving along line joining him and source, he hears 10 beats per second. Velocity of man is : (Frequency of source = 60 Hz, Velocity of sound = 330 m/s)

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