1.

a man is four times old as his son. 20 years hence he will be twice as old as his son. find their present ages. answer

Answer»

Let the present age of SON be X YEARS
Then, The present age of MAN is 4x years
Twenty years hence,
Man's age = 4x + 20
Son's age = x + 20
Given:
4x + 20 = 2 ( x + 20 )
4x + 20 = 2x + 40
2x = 20
x = 10
Hence. the present age of man is 40 years
And, his son's present age is 10 years



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