1.

a man is 4 times as old as his son after 16 years he will be only twice as old as his son find their present age

Answer»

Let age of SON = x
so MAN's age = 4x
sons age after 16 years = x+16
man's age after 16 years = 4x+16
ATQ
2(x+16) = 4x+16
2x+32=4x+16
2x-4x=16-32
-2x= -16
2x = 16
x= 16/2
x= 8

Son's age = 8 yrs
Man's age = 4×8 = 32 years


Hope it helps.
Brainliest pls I beg U



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