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A man invests 1200 for two years at compound interest. After one year the money amounts to 1275. Find the interest for second year correct to the nearest rupee |
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Answer» Step-by-step EXPLANATION: interest=1275-1200=75 rate=(75×100)/1200×1 =25/4 interest=1275×25/4×1/100 =31875/400 =79.6875 total interest=75+79.68 154.68 |
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