1.

A man invests 1200 for two years at compound interest. After one year the money amounts to 1275. Find the interest for second year correct to the nearest rupee

Answer»

Step-by-step EXPLANATION:

interest=1275-1200=75

rate=(75×100)/1200×1

=25/4

interest=1275×25/4×1/100

=31875/400

=79.6875

total interest=75+79.68

154.68



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