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A man goes 5 m in east and then 12 m in north direction. Find the distance from the staring point. |
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Answer» Step-by-step explanation: Let the initial position of the man be O and his final position be B. Since the man goes 10 m due EAST and then 24 m due north. Therefore, △AOB is a right triangle right-angled at A such that OA=10 m and AB=24 m. By pythagoras theoram, we have OB^2 =OA^2 +AB^2 OB^2 =10^2 +24^2 =100+576=676 OB= √676 =26m Hence, the man is at a distance of 26m from the STARTING POINT. |
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