A man goes 24 m due West and then7 m due North. Then, he is .........

1.	A man goes 24 m due West and then7 m due North. Then, he is ......... m awayfrom the starting point.
Answer» ᴴeʸ ᵐaᵗe ʰeʳe iˢ ʸouʳ aⁿˢʷeʳ⁻ We can SEE in the FIGURE attached that - He goes 24m west and 7m north. So to find the DISTANCE between the starting and ending point, we will apply pythagoras theoram. So LET the distance be x So, x^2= (24)^2+7^2 x^2=576+49 x^2=625 x=√625 x=25 m So the answer is 25m.

A man goes 24 m due West and then7 m due North. Then, he is ......... m awayfrom the starting point.

Answer»

ᴴeʸ ᵐaᵗe ʰeʳe iˢ ʸouʳ aⁿˢʷeʳ⁻

We can SEE in the FIGURE attached that -

He goes 24m west and 7m north.

So to find the DISTANCE between the starting and ending point, we will apply pythagoras theoram.

So LET the distance be x

So,

x^2= (24)^2+7^2

x^2=576+49

x^2=625

x=√625

x=25 m

So the answer is 25m.

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A man goes 24 m due West and then7 m due North. Then, he is ......... m awayfrom the starting point.​