A man fires a bullet of mass 200 g at a speed of 5m/s. the gun is of o

1.	A man fires a bullet of mass 200 g at a speed of 5m/s. the gun is of one kg mass, by how much velocity the gun rebound backwards.
Answer» m1 - mass of bullet = 200 g = 0.2 kg m2 - mass of GUN = 1 kg V1 - VELOCITY of bullet = 5 m/s V2 - velocity of gun = ?? ACCORDING to law of conservation of linear momentum, Linear momentum=Linear momentum before firing after firing 0 = m1 V1 + m2 V2 V2 = - m1 V1/m2 = - 0.2×5×1 V2 = - 1 m/s Velocity of the gun = -1 m/s.

A man fires a bullet of mass 200 g at a speed of 5m/s. the gun is of one kg mass, by how much velocity the gun rebound backwards.

Answer»

m1 - mass of bullet = 200 g = 0.2 kg

m2 - mass of GUN = 1 kg

V1 - VELOCITY of bullet = 5 m/s

V2 - velocity of gun = ??

ACCORDING to law of conservation of linear momentum,

Linear momentum=Linear momentum

before firing after firing

0 = m1 V1 + m2 V2

V2 = - m1 V1/m2

= - 0.2×5×1

V2 = - 1 m/s

Velocity of the gun = -1 m/s.

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A man fires a bullet of mass 200 g at a speed of 5m/s. the gun is of one kg mass, by how much velocity the gun rebound backwards.

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