1.

A man covers a certain distance between his house and office on a scooter having average speed 30 kmph. He is late by 10 mins, however with the speed of 40 kmph he reaches his office 5 min. Earlier. Find the distance between his house and office?a.30 kmb.50 km

Answer»

Let US assume that your SCHOOL TIME is 9:00 AM.
let us assume you reaches school 10 min late, therefore you reaches at 9:10 AM
and let us think that your friend reaches 5 min earlier, therefore he reaches at 8:55 AM.
the DIFFERENCE in time is 10+5 = 15 min.
hope this helps you.



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