1.

A man can swim in still water at a speed of 6kmph and he has to cross the river and reach just opposite point on the other bank. if the river is flowing at a speed of 3kmph, he has to swim in the direction

Answer»

Final ANSWER : tan^{-<klux>1</klux>}(1/2) with the vertical.

Steps :
1) Man has to swim in such a way that, he WANT to reach just opposite point on the other bank.
=> Drift is 0 .

2)Speed of River is 3km/h in horizontal direction.
=> For Drift to be zero, Horizontal component of velocity of man should be 3km/h leftward.
as SHOWN. We get,
|v_x| = 3 km/h \\ |v_y| = 6 km/h \\ => \tan(\theta) = \frac{|v_x|}{|v_y|} \\ => \tan(\theta) = \frac{1}{2}

Hence, Man has to swim by making angle \theta with vertical.


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