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A man can open a nut by applying a force of 100kgf by using a lever of handle of 3m. What should be length of a lever of another handle if the force required to open the nut is 60kgf? ​

Answer» FORCE of applying to open a NUT be F1=150N Force applied on opening it at the length of the handle F2 =60N Lever handle of length L2=0.4 m ATP:- F1×L1=F2×L2 150×0.4=60×L2 (Which we have to find....)  (150×4)/10×60=L2  THEREFORE L2=1m  Hence, the Length of handle will the MAN be able to open by applying a force of 60N=1m  HOPE THIS HELPS..


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