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A major textile dye manufacturer developed a new yellow dye. The dye has a percent composition of 75.95% C, 17.72% N, and 6.33% H by mass with a molar mass of about 240 g/mol. Determine the molecular formula of the dye.

Answer»

ercentage composition:C = 75.95%N = 17.72%H = 6.33% Molar mass = 240 gmTo Find:The molecular formula of the dye.Calculation:- Let the mass of compound be 100 gm.⇒ Mass of C = 75.95 gm⇒ Mass of N = 17.72 gm⇒ Mass of H = 6.33 gm - No of moles:C = 75.95/12 = 6.33N = 17.72/14 = 1.27H = 6.33/1 = 6.33- Simplest ratioC = 6.33/1.27 = 4.98 ≈ 5N = 1.27/1.27 = 1H = 6.33/1.27 = 4.98 ≈ 5- Empirical formula = C5NH5- Empirical formula mass = 12 × 5 + 14 + 1 × 5 = 79 gm- n = Molar mass/ Empirical formula mass ⇒ n = 240/79 = 3.04 ≈ 3- Molecular formula = Empirical formula × n⇒ Molecular formula = C15N3H15(Note: The molar mass given is approximate. ACTUAL molar mass is 237 gm/mol)



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