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a magnetising field of 1500A/m produces flux of 2.4*10^-5 weber in a iron bar of cross section area of .5 cm^2 . the permeability of iron bar is |
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Answer» agnetic INDUCTION B = flux / area is to be found out. B = 2.4 x 10-5 / 0.2 x 10-4 = 1.2 TNow PERMEABILITY u = B / HGiven H = 1600 A/m, and found B = 1.2 TSo u = 7.5 x 10-4 H/mCONGRATS! FRIEND Mukul is rightNow with susceptibility chi we have to follow u / UO = 1 + chiuo = 4 pi x 10-7By the by chi = 596 (nearly) |
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