Saved Bookmarks
| 1. |
a machine gun having weight 20 kg fire bullet of 35g at rate of 400 bullet per minute at speed of 400 m per second. now what is force required to hold the gun at the same place. |
|
Answer» machine GUN weight = 20 kg weight of bullet = 35g = 0.035 kg speed of bullet = 400 m/s impulse from ONE bullet = MV = 0.035×400 = 14 kg.m/s number of BULLETS per second = 400/60 = 20/3 impulse per second = 14 × 20/3 = 280/3 = 93.33 kg.m/s/s = 93.33 kg.m/s² = 93.33 N (Impulse per second is nothing but force) You need 93.33 N force to hold the gun in place. |
|