1.

a machine gun having weight 20 kg fire bullet of 35g at rate of 400 bullet per minute at speed of 400 m per second. now what is force required to hold the gun at the same place.

Answer» machine GUN weight = 20 kg

weight of bullet = 35g = 0.035 kg
speed of bullet = 400 m/s
impulse from ONE bullet = MV = 0.035×400 = 14 kg.m/s

number of BULLETS per second = 400/60 = 20/3
impulse per second = 14 × 20/3 = 280/3 = 93.33 kg.m/s/s = 93.33 kg.m/s² = 93.33 N

(Impulse per second is nothing but force)

You need 93.33 N force to hold the gun in place.



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