1.

A longitudinal wave is described by the equation y = y_(0) sin 2pi (ft - x// lambda) . The maximum particle velocity is equal to four times the wave velocity if ……….. .

Answer»

`lambda = pi y_(0)//4`
`lambda = pi y_0//2`
`lambda = 4 pi y_(0)`
`lambda = 2 pi y_(0)`

Solution :Particle velocity ` v= (dy)/(DT) = 2 pi y_(0) COS {2 pi (FT - x// lambda)}`
`v_("max") = 2pi fy_0`
`v_("max") = 2pi f y_(0) = 4 f lambda`
`implies lambda = (pi y_(0))/(2)`


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