1.

A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is _______ .

Answer»

B
2B
4B
`B/2`

Solution :A LONG solenoid carrying a current produces magnetic field B along its AXIS.
Now if the current I is doubled and the NUMBER of turns N per cm is halved the magnetic field
`B.=mu_(0)n/2xx2I=Bmu_(0)nI=B`


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