A load of mass 20 kg is lifted with the help of a rope at a constant a

1.	A load of mass 20 kg is lifted with the help of a rope at a constant acceleration. The load covers a height of 5 m in 2 seconds. Calculate the tension in the rope. In a rocket m changes with time. Write down the mathmatical form of newton's law in this case and interpret it physically.
Answer» Answer: 250 N Explanation: m= 20 kg s=5m t=2s T-mg = ma ( by free BODY DIAGRAM) T =ma + mg =m(a+g) s= UT + 1/2 at^2 5= (02) + 1/2 a* 4 a= 5/2 = 2.5 T = 20 ( 2.5 + 10) taking g= 10 T = 20 * 12.5 = 250 N

A load of mass 20 kg is lifted with the help of a rope at a constant acceleration. The load covers a height of 5 m in 2 seconds. Calculate the tension in the rope. In a rocket m changes with time. Write down the mathmatical form of newton's law in this case and interpret it physically.

Answer»

Answer:

250 N

Explanation:

m= 20 kg s=5m t=2s

T-mg = ma ( by free BODY DIAGRAM)

T =ma + mg

=m(a+g)

s= UT + 1/2 at^2

5= (0*2) + 1/2 * a* 4

a= 5/2 = 2.5

T = 20 ( 2.5 + 10) taking g= 10

T = 20 * 12.5 = 250 N

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A load of mass 20 kg is lifted with the help of a rope at a constant acceleration. The load covers a height of 5 m in 2 seconds. Calculate the tension in the rope. In a rocket m changes with time. Write down the mathmatical form of newton's law in this case and interpret it physically.

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