1.

A liquid rises to a height of 9 cm in a glass capillary tube of radius 0.02 cm. What will be the height of the liquid column in a glass capillary tube of radius 0.03 cm ?

Answer»

Data : h1 = 9 cm, r1 = 0.02 cm, r2 = 0.03 cm

For the first capillary, T = \(\frac{r_1h_1pg}{2\,cos\,\theta}\)

For the second capillary, T = \(\frac{r_2h_2pg}{2\,cos\,\theta}\)

∴ \(\frac{r_1h_1pg}{2\,cos\,\theta}\) - \(\frac{r_2h_2pg}{2\,cos\,\theta}\)

∴ r1h1= r2h2

The height of the liquid column in the second capillary,

h2 = \(\frac{r_1h_1}{r_2}\) = \(\frac{0.02\times9}{0.03}\) = 6 cm



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