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A liquid rises to a height of 9 cm in a glass capillary tube of radius 0.02 cm. What will be the height of the liquid column in a glass capillary tube of radius 0.03 cm ? |
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Answer» Data : h1 = 9 cm, r1 = 0.02 cm, r2 = 0.03 cm For the first capillary, T = \(\frac{r_1h_1pg}{2\,cos\,\theta}\) For the second capillary, T = \(\frac{r_2h_2pg}{2\,cos\,\theta}\) ∴ \(\frac{r_1h_1pg}{2\,cos\,\theta}\) - \(\frac{r_2h_2pg}{2\,cos\,\theta}\) ∴ r1h1= r2h2 The height of the liquid column in the second capillary, h2 = \(\frac{r_1h_1}{r_2}\) = \(\frac{0.02\times9}{0.03}\) = 6 cm |
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