A line passing througjh the point of intersection of x+y=4 and x−y=2 – InterviewSolution

1.	A line passing througjh the point of intersection of x+y=4 and x−y=2 makes an angle of tan−134 with the x axis. It intersects the parabola y2=4(x−3) at point (x1,y1) and (x2,y2) respectively. Then \|x1−x2\| is equal to;
Answer» A line passing througjh the point of intersection of $x + y = 4$ and $x - y = 2$ makes an angle of ${tan}^{- 1} \frac{3}{4}$ with the $x$ axis. It intersects the parabola $y^{2} = 4 (x - 3)$ at point $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ respectively. Then $\| x_{1} - x_{2} \|$ is equal to;

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