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A line AB cut off intercepts on the axes in such a way that the sum and the product of the intercepts are 1 and -6 respectively, then find the value of a and b.Please help please please please please please please please please please please please please please please please please please please please please please please please please |
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Answer» Answer: Equation of a line by INTERCEPT form is a x
+ b y
=1 where a=x-intercept b=y-intercept But GIVEN that x and y intercept are EQUAL in magnitude but OPPOSITE in sign ∴a=−b or b=−a Thus, equation of line is a x
− a y
=1 x−y=a x−y−a=0......(1) Since the line is PASSING through (2,3) ∴ Point (2,3) will satisfy equation of line Putting x=2 and y=3 in (1) 2−3−a=0 −1−a=0 a=−1 Now, equation of line become x−y+1=0 This is the required equation. |
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