A light rod of length L can revolve in a vertical circle around point O. The rod carries two equal masses of mass m each such that one mass is connected at the end of the rod and the second mass is fixed at the middle of the rod. u is the velocity imparted to the end P to deflect the rod to the horizontal position. Again mass m in the middle of the rod is removed and mass at end P is doubled. Now v is the velocity imparted to end P to deflect it to the horizontal position. Then (uv)2 is

A light rod of length L can revolve in a vertical circle around point

1.	A light rod of length L can revolve in a vertical circle around point O. The rod carries two equal masses of mass m each such that one mass is connected at the end of the rod and the second mass is fixed at the middle of the rod. u is the velocity imparted to the end P to deflect the rod to the horizontal position. Again mass m in the middle of the rod is removed and mass at end P is doubled. Now v is the velocity imparted to end P to deflect it to the horizontal position. Then (uv)2 is
Answer» A light rod of length $L$ can revolve in a vertical circle around point $O$ . The rod carries two equal masses of mass $m$ each such that one mass is connected at the end of the rod and the second mass is fixed at the middle of the rod. $u$ is the velocity imparted to the end $P$ to deflect the rod to the horizontal position. Again mass $m$ in the middle of the rod is removed and mass at end $P$ is doubled. Now $v$ is the velocity imparted to end $P$ to deflect it to the horizontal position. Then ${(\frac{u}{v})}^{2}$ is

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