A light ray is incident on a rectangular glass slab at an angle of 60�

1.	A light ray is incident on a rectangular glass slab at an angle of 60°. What is the angle between the ray coming out of the slab and the normal to the face of rectangular slab from which it comes out?
Answer» Ray of light strikes the mirror at an angle of 60°. ⇒ It will make an angle of 300 (900 – 600) with the normal. ∴ Angle of incidence = 300. Now, By laws of refraction; µ = \(\frac{Sin\,i}{Sin\,r}\) Angle of incidence is 60° Refractive index of glass slab is 1.5 Putting the value in the above equation, we get 1.5 = \(\frac{0.866}{sin\,r}\) On solving the above equation, we get sin r = \(\frac{0.866}{1.5}\) Angle of refraction, r= 35.26° Thus the angel of refraction is 35.26° from the normal.

A light ray is incident on a rectangular glass slab at an angle of 60°. What is the angle between the ray coming out of the slab and the normal to the face of rectangular slab from which it comes out?

Answer»

Ray of light strikes the mirror at an angle of 60°.

⇒ It will make an angle of 300 (900 – 600) with the normal.

∴ Angle of incidence = 300.

Now, By laws of refraction;

µ = \(\frac{Sin\,i}{Sin\,r}\)

Angle of incidence is 60°

Refractive index of glass slab is 1.5

Putting the value in the above equation, we get

1.5 = \(\frac{0.866}{sin\,r}\)

On solving the above equation, we get

sin r = \(\frac{0.866}{1.5}\)

Angle of refraction, r= 35.26°

Thus the angel of refraction is 35.26° from the normal.