A light ray, going through a prism with the angle of prism 60°, is found to deviate by 30°. What limit on the refractive index can be put from these data

A light ray, going through a prism with the angle of prism 60°, is fo

1.	A light ray, going through a prism with the angle of prism 60°, is found to deviate by 30°. What limit on the refractive index can be put from these data
Answer» ANGLE of PRISM =60Angle of deviation= 30μ= sin(A+Dm)/2 / Sin A/2μ= Sin (60 +Dm)/2/ Sin 30We know that ONE ray has been found out which is DEVIATED by 30°, the angle of minimum deviation should be either equal or less than 30°. μ≤2sin 60+dm/2 μ≤2x1/√2 μ≤√2

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A light ray, going through a prism with the angle of prism 60°, is found to deviate by 30°. What limit on the refractive index can be put from these data

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