1.

A lift is moving up with a constant retardation of 2 m//s^(2). When its upward velocity is 5 m/s, a boy in the lift tosses a coin, imparting it an upward velocity of 3 m/s, w.r.t. himself. His fingers at the moment of toss are midway between the floor and cciling, whose total height is 2 m. Displacement of coin when it hits the ground is x metre (in earth frame). Value of x is : (g = 10 m//s^(2))

Answer»


SOLUTION :INITIAL VELOCITY of coin `= 2 m//s`
Acceleration `= - 10 m//s^(2)`
Now, `h = ut + (1)/(2) a t^(2)`


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