1.

A lift is ascending by acceleration g//3. What will be the time period of a simple pendulum suspended from its ceiling if its time period in stationary lift is T?

Answer»

`(T)/(2)`
`((sqrt3)/(2))xxT`
`sqrt3(T)/(4)`
`(T)/(4)`

SOLUTION :Here `T_(E) = 2pisqrt((l)/(g_(e)))g_(e)=`effective value of g.,br>Now `g-(e)=g+(g)/(3)=(4g)/(3)`
`T_(e)=2pisqrt((lxx3)/(4g))=(sqrt3)/(2)xx2pisqrt((l)/(g))=((sqrt3)/(2)).T`
(b) is the CHOICE


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