1.

A lens of focal length 12 CM forms and erect image three times the size of the object. The distance between the object and image is:

Answer»

16 cmExplanation:f = 12 cmLet size of object be 'h' cm.size of image = '3h' cmTherefore, magnification = 3h/h = v/uv/u = 3h/h=> v/u = 3=> v = 3uNow, from LENS FORMULA we get —1/v - 1/u = 1/f=> 1/3u - 1/u = 1/12=> -2/3u = 1/12=> u = - 8 cm ( '-' SIGN DENOTES that it is on the left side of the lens)Hence, v = 3u = -24 cm ( again '-' sign denotes it is on the left side of the lens)Therefore, distance between the object and image is,= v - u= (24 - 8) cm= 16 cm.



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