Saved Bookmarks
| 1. |
A lens has focal length f. It gives diffraction pattern of Fraunhoffer type of a slit giving width of w. If the wavelenth of light used is lambda, then what is the distance of first dark band and next bright band from axis? |
|
Answer» `(a)/(lambda)F` n = 1 `sin theta = (lambda)/(omega)` `Rightarrow theta = (lambda)/(omega)` If distance of FIRST dark fringe is x, then `theta = (x)/(f)`. So, `(x)/(f) = (lambda)/(a), x = (lambda)/(a)f`. |
|