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A leap of 1m can be taken in 1s after every 5 leaps taken in the forward direction, leaps in the backward direction will be taken. In a journey of 13m of displacementPlease answer me fast and correct explanation I will mark you as a brainlist |
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Answer» Answer: L. H. S. = Sec⁴ θ ( 1 - Sin ² θ )² - 2 tan² θ => Sec⁴ θ ( cos² θ )² - 2 tan²θ => sec ⁴ θ × cos⁴ θ - 2 tan² θ => ( 1 / Cos⁴ θ ) × cos⁴ θ - 2 tan² θ => 1 - 2tan ² θ => 1 - 2 sin² θ/ Cos² θ => ( cos² θ - 2 sin² θ ) / Cos² θ => [cos ² θ - 2 ( 1 - cos² θ)] /Cos ² θ => ( cos² θ - 2 + 2 cos² θ ) /cos² θ =>[ cos² θ ( 1 - 2 +2 )] /Cos ² θ => 1 = R. H. S. Explanation: |
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