A lead bullet of mass 10 g travelling at 300 m/s strikes against a block of wood and comes to rest. Assuming 50% of heat is absorbed by the bullet, find the increase in its temperature. (Specific heat of lead = 150 J Kg^(-1)k^(-1))

A lead bullet of mass 10 g travelling at 300 m/s strikes against a blo

1.	A lead bullet of mass 10 g travelling at 300 m/s strikes against a block of wood and comes to rest. Assuming 50% of heat is absorbed by the bullet, find the increase in its temperature. (Specific heat of lead = 150 J Kg^(-1)k^(-1))
Answer» SOLUTION :Loss in K.E. = Heat energy `1/2xx 1/2xx 10/(1000) xx (300)^(2) = 10/(1000) xx 150 xx DELTATHETA` `implies` rise in TEMPERATURE `Deltatheta = 150^(0)C`