1.

A lead bullet just melts when stopped by an obstacle. Assuming that 25% of heat is absrobed by the obstacle find the velocity of the bullet if the initial temperature was 27^(@)C. Melting point of lead = 327^(@)C, specific heat of lead =0.03 cal g ^(-1) ""^(@)C ^(-1).Latent heat of fusion of lead =6 cal g ^(-1).

Answer»

Solution :`(3//4) xx (1//2)MV ^(2) = mcd T+ mL , c =126 JKG ^(-1) K ^(-1) , L = 2. 52 xx 10 ^(4) J//kg, v = 409.9 MS ^(-1)`


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