A launching pad with a spaceship is moving along a circular orbit of the moon, whose radius R is triple that of the moon Rm. The ship leaves the launching pad with a relative velocity equal to the launching pad's initial orbital velocity V0 and the launching pad then falls to the moon. If the angle θ=cos−1 n√10 with the horizontal is the angle at which the launching pad crashes into the surface and its mass is twice that of the spaceship, then the value of n is

A launching pad with a spaceship is moving along a circular orbit of t

1.	A launching pad with a spaceship is moving along a circular orbit of the moon, whose radius R is triple that of the moon Rm. The ship leaves the launching pad with a relative velocity equal to the launching pad's initial orbital velocity V0 and the launching pad then falls to the moon. If the angle θ=cos−1 n√10 with the horizontal is the angle at which the launching pad crashes into the surface and its mass is twice that of the spaceship, then the value of n is
Answer» A launching pad with a spaceship is moving along a circular orbit of the moon, whose radius $R$ is triple that of the moon $R_{m}$ . The ship leaves the launching pad with a relative velocity equal to the launching pad's initial orbital velocity $V_{0}$ and the launching pad then falls to the moon. If the angle $θ = c o s^{- 1} \frac{n}{\sqrt{10}}$ with the horizontal is the angle at which the launching pad crashes into the surface and its mass is twice that of the spaceship, then the value of $n$ is

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