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A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water, the quantities of water flowing out per second from both holes are the same. Then, R is equal toA. `(L)/sqrt(2pi)`B. `2 pi L`C. `L`D. `(L)/(2pi)` |
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Answer» Correct Answer - A Volume flowing per sec `V=av` `L^(2)sqrt(2gy)=pir^(2)sqrt(2g(4y))" "impliesL^(2)=2piR^(2)` `R=(L)/sqrt(2pi)` |
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