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A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water, the quantities of water flowing out per second from both holes are the same. Then, R is equal toA. `L//sqrt(2pi)`B. `2piL`C. `L`D. `1//2pi` |
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Answer» Correct Answer - A Equating the rate of flow, we have `sqrt((2gy))xxL^(2)=sqrt((2gxx4y))piR^(2)` `impliesL^(2)=2piR^(2)impliesR=L/sqrt((2pi))` Flow `=("area")xx("velocity")`. Here `Vel=sqrt(2gx)` where `x=ht` from top |
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