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A large number of liquid drops each of radius a are merged to form a single sperical drop of radius b the energy released in the process is converted into kinetic energy of the bigh drop formed the speed of the bigh drop is [p density of liquid T= surface tension of liquid]A. `[(6T)/(rho)(1/a-1/b)]^(1//2)`B. `[(6T)/(rho)(1/b-1/a)]^(1//2)`C. `[(rho)/(6T)(1/a-1/b)]^(1//2)`D. `[(rho)/(6T)(1/b-1/a)]^(-1//2)` |
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Answer» Correct Answer - a Suppose n number of liquid drops are merged equating initial and final volume we have `v_(i)=v_(t)` `rarr n xx 4/3 pi a^(3)=4/3 pi b^(3)` `rarr b=(n)^(1//3)a rarr n =(b/a)^(3)` initial surface energy `u_(i)=nxx 4pi a^(2)xxS` final surface energy `u_(f)=4pib^(2)xxS` change in surface energy speed of the bigger drop `v=[(6T)/(p)(1/a-1/b)]^(1//2)` |
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